Trigonometry (1)

Geometry Level 3

Find the value of x x and y y in the following tan ⁡ 2 ( x + y ) + cot ⁡ 2 ( x + y ) = 1 − 2 x − x 2 \tan^2(x+y)+\cot^2(x+y)=1-2x-x^2 .

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x = − 1 , y = ( 4 n π + π + 4 ) ( 3 ) x=-1,y=\frac{(4n\pi+\pi+4)}{(3)} x = − 1 , y = ( 4 n π + π + 4 ) ( 4 ) x=-1,y=\frac{(4n\pi+\pi+4)}{(4)} x = − 4 , y = ( 4 n π + π + 4 ) ( 4 ) x=-4,y=\frac{(4n\pi+\pi+4)}{(4)} x = − 1 , y = ( 4 n π + π + 6 ) ( 4 ) x=-1,y=\frac{(4n\pi+\pi+6)}{(4)}

Sahil Silare by Sahil Silare , 20, India

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1 solution

Tapas Mazumdar
Aug 8, 2016

3 Helpful 1 Interesting 1 Brilliant 0 Confused

Hi, can you help me with this please: Exam question

Syed Hamza Khalid - 1 year, 5 months ago

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