A rectangular piece of paper can be rolled into a tube in two different ways. (Edges should not overlap.)
When it is rolled up the long way the volume enclosed is
When it is rolled up the short way the volume enclosed is
Find the area of the piece of paper in
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Call the dimensions x and y .
It is simple enough to show the volumes are 4 π x 2 y and 4 π x y 2
This gives x 2 y = 1 0 0 0 0 and x y 2 = 1 2 5 0 0
Solve the first equation for y and substitute into the second
x ( x 2 1 0 0 0 0 ) 2 = 1 2 5 0 0
x 3 = 1 2 5 0 0 1 0 0 0 0 2
x = 2 0
Similarly y = 2 5
x y = 2 0 ∗ 2 5 = 5 0 0