∫ 2 0 1 3 ( x − 1 ) 2 0 1 2 ( x + 1 ) 2 0 1 4 d x
Given that the integral above is defined for x > 1 . Ignoring the arbitrary constant, it evaluates to β α ( x + μ x − λ ) σ / θ where α , β , λ , μ , σ , θ are positive integers with g cd ( α , β ) = g cd ( σ , θ ) = 1 . Find the value of α + β + λ + μ + σ + θ + 6 0 3 3 .
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@Vishwak Srinivasan Your image has not been properly uploaded. Re-upload it!
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Uploaded. @Satyajit Mohanty
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Good. I really don't understand how @Joseph Gomes found the answer 10064 when my problem was set wrong. I hadn't corrected the problem till then.
You can also take (x-1)/(x+1) =t and then integrate
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Sorry for the image solution.