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Algebra Level 3

A student took five papers in an examination, where the full marks were the same for each paper . his marks in these papers were in the proportion 6:7:8:9:10. He obtained 3 5 \frac 3 5 part of the total full marks. Then the number of papers in which he got more than 50 % marks is?

3 5 4 2

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2 solutions

Finn Hulse
Apr 9, 2015

We can write that 6 / x + 7 / x + 8 / x + 9 / x + 10 / x = 3 / 5 6/x+7/x+8/x+9/x+10/x=3/5 , where we let x x be the full amount of possible points of all 5 papers. Thus 40 / x = 3 / 5 40/x=3/5 and x = 200 / 3 x=200/3 . Then each test was worth 40 / 3 40/3 . We are looking for anything above a 20 / 3 20/3 , which is 50%, which is 6.66666, thus 7, 8, 9, and 10 work and the answer is 4 \boxed{4} .

Charlz Charlizard
Jun 26, 2015

Let the person in the 3rd paper(Which is referenced) score Y marks, so (6+7+8+9+10)/8 Y X=5 X 3/5..Where X is max marks obtained in single paper..So Y=3/5=0.6..So in 2nd paper his % score=0.6 7/8=0.525..In 1st paper he scored 0.525 6/7= 0.45..So except 1st, he scored>0.5 in all the papers..making it to 4..

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