Karen has three times the number of cherries that Lionel has, and twice the number
of cherries that Michael has. Michael has seven more cherries than Lionel. How
many cherries do Karen, Lionel and Michael have altogether?
This problem is not original.This problem is part of this set .
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Let Lionel have (\x) cherries. Therefore cherries with Karen are 3 x and cherries with Michael are x + 7 .
It is given that Karen has twice the number of cherries with Michael. Therefore:
2 ( x + 7 ) = 3 x 2 x + 1 4 = 3 x x = 1 4
From that, we can find out the cherries: 1 4 + 4 2 + 2 1 = 7 7