UKMT Senior Challenge-XII

Algebra Level 3

Karen has three times the number of cherries that Lionel has, and twice the number of cherries that Michael has. Michael has seven more cherries than Lionel. How many cherries do Karen, Lionel and Michael have altogether?

This problem is not original.This problem is part of this set .


The answer is 77.

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1 solution

Aryan Gaikwad
Mar 11, 2015

Let Lionel have (\x) cherries. Therefore cherries with Karen are 3 x 3x and cherries with Michael are x + 7 x+7 .

It is given that Karen has twice the number of cherries with Michael. Therefore:

2 ( x + 7 ) = 3 x 2 x + 14 = 3 x x = 14 2(x+7)=3x\\ 2x+14=3x\\ x=14

From that, we can find out the cherries: 14 + 42 + 21 = 77 14 + 42 + 21 = \boxed{77}

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