Under pressure 2!!

Classical Mechanics Level 2

A cylinder has a volume of 3m^3 containing gas with 250K temperature and a pressure of 50000Pa. Another cylinder has a volume of 7.2m^3 containing gas with 400K temperature and a pressure of 20000Pa. If we connect the two cylinders by a connecting tube and not changing the temperature,what will be the pressure in the end?

3.4*10^3Pa 4.1*10^4Pa 3.2*10^4Pa 3*10^4Pa

Fahim Muhtamim by Fahim Muhtamim , 17, Bangladesh

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

The pressure is given by p = p 1 V 1 T 1 + p 2 V 2 T 2 V 1 T 1 + V 2 T 2 p=\dfrac{\dfrac{p_1V_1}{T_1}+\dfrac{p_2V_2}{T_2}}{\dfrac{V_1}{T_1}+\dfrac{V_2}{T_2}} where p 1 = 50000 , V 1 = 3 , T 1 = 250 , p 2 = 20000 , V 2 = 7.2 , T 2 = 400 p_1=50000, V_1=3, T_1=250, p_2=20000, V_2=7.2, T_2=400 . So the final pressure is obtained after substitution to be equal to 32000 32000 Pa or 3.2 ∗ 1 0 4 3.2*10^4 Pa

0 Helpful 0 Interesting 0 Brilliant 0 Confused

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...