A diver at a depth of 12 m in water sees the sky in a cone of semi vertical angle
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Refractive index of water is approximately 3 4 , which should have been mentioned.
Taking the semi vertical angle as θ , and applying Snell's Law
3 4 × sin θ = s i n ( 2 π )
So, sin θ = 4 3
So, θ = s i n − 1 ( 4 3 )