Uniform line charge

Electricity and Magnetism Level 2

A uniform line charge with linear density λ \lambda lies along the y y -axis. What is the flux that crosses the spherical surface with radius R R centered at the origin?

R λ ε 0 \frac{R\lambda}{\varepsilon_{0}} R λ 2 ε 0 \frac{R\lambda}{2\varepsilon_{0}} λ ε 0 \frac{\lambda}{\varepsilon_{0}} 2 R λ ε 0 \frac{2R\lambda}{\varepsilon_{0}}

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Srinivasa Satti by Srinivasa Satti

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1 solution

Charge enclosed is 2 λ R 2λR As we know, flux = charge enclosed/ε

Therefore, Φ = 2 λ R / ε \boxed{Φ=2λR/ε}

2 Helpful 0 Interesting 0 Brilliant 0 Confused

How is that we calculate charge inside as 2Rlamda?

revathi sekar - 3 years, 7 months ago

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