Uniformity Area

We can start by calculating what $K$ is.

$K=7-3=4$

$\frac{K}{3}=\frac{4}{3}=1.333...\ \\ \frac{3}{1.333...}=2.25$

Now using the Pythagorean Theorem, we can determine the height of the smaller parallelogram.

$a^{2}+b^{2}=c^{2} \\ a=3-2 \\ c=2.25 \\ 1^{2}+b^{2}=2.25^{2} \\ b^{2}=5.0625-1 \\ b=\sqrt{4.0625} \\ A_{Triangle}=\frac{b \times 1}{2} \\ A_{Triangle}=\frac{2.0155... \times 1}{2} \\ A_{Triangle}=1.00778... \\ A_{Triangle}>1$

You could also say if $b^{2}>4$ then $b>2$ and therefore the area will be greater than 1.