unit digit

Find the units digit of 2011! + 2012! + 2013! + 2014! + 2015!


The answer is 0.

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1 solution

As 2 is less than 5, then 2011 5 + 2011 25 + 2011 125 + 2011 625 = 402 + 80 + 16 + 3 = 501 \left\lceil \frac { 2011 }{ 5 } \right\rceil +\left\lceil \frac { 2011 }{ 25 } \right\rceil +\left\lceil \frac { 2011 }{ 125 } \right\rceil +\left\lceil \frac { 2011 }{ 625 } \right\rceil =402+80+16+3=501 implies that 2011! ends in 501 zeros. The same with 2012!, 2013! and 2014!. In fact, 2015! ends with 502 zeros

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