United a-z of coefficient

Algebra Level 2

( 1 a 1 + 2 b 2 3 c 3 + 4 d 4 25 y 25 + 26 z 26 ) θ (-1a^{-1}+2b^2-3c^{-3}+4d^4-……………-25y^{-25}+26z^{26})^\theta

a,b,c,d,e,……,y,z are variables.

The sum of coefficients in expansion of above expression has 9 digits.

What is the value of θ \theta ?


Clue: Title of the problem.


This is an original problem and belongs to my set Raju Bhai's creations


The answer is 8.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Rajath Rao
Dec 24, 2017

For any expression, to find sum of coefficients, we need to substitute 1 in variables.

If we substitute 1 in above expression, we get,

( 1 + 2 3 + 4 25 + 26 ) θ (-1+2-3+4-……-25+26)^\theta


Sum of even numbers = n ( n + 1 ) = 13 ( 13 + 1 ) n(n+1)=13(13+1)

Sum of odd numbers= n 2 = 1 3 2 n^2=13^2

( 2 + 4 + 6 + 26 ) ( 1 + 3 + 5 + 25 ) = 13 ( 13 + 1 ) 1 3 2 = 13 (2+4+6…+26)-(1+3+5…+25)=13(13+1)-13^2=13


Sum of coefficients= 1 3 θ 13^\theta

Given that ,the sum of coefficients has 9 digits.

Therefore, θ = 8 \boxed{\theta=8}

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...