a,b,c,d,e,……,y,z are variables.
The sum of coefficients in expansion of above expression has 9 digits.
What is the value of ?
Clue: Title of the problem.
This is an original problem and belongs to my set Raju Bhai's creations
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For any expression, to find sum of coefficients, we need to substitute 1 in variables.
If we substitute 1 in above expression, we get,
( − 1 + 2 − 3 + 4 − … … − 2 5 + 2 6 ) θ
Sum of even numbers = n ( n + 1 ) = 1 3 ( 1 3 + 1 )
Sum of odd numbers= n 2 = 1 3 2
( 2 + 4 + 6 … + 2 6 ) − ( 1 + 3 + 5 … + 2 5 ) = 1 3 ( 1 3 + 1 ) − 1 3 2 = 1 3
Sum of coefficients= 1 3 θ
Given that ,the sum of coefficients has 9 digits.
Therefore, θ = 8