If x is a positive integer, what is the unit digit of ( 2 4 ) 5 + 2 x ( 3 6 ) 6 ( 1 7 ) 3 = ?
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Nice solution, but there is an easier way to tackle this. Let's look at 2 4 5 + 2 x , we know that powers of 4 ends with 4 if the power is odd and 6 if the power is even.
Since 5 + 2 x is odd ⟹ the unit digit of 2 4 5 + 2 x is 4
Powers of 6 always ends with 6 and finally 7 3 = 3 4 3 ⟹ 4 × 6 × 3 = 7 2 ⟹ the unit
digit is 2 .
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2 4 5 + 2 x ⋅ 3 6 6 ⋅ 1 7 3 ≡ 5 7 6 x ⋅ 4 5 ⋅ 6 6 ⋅ 7 3 ≡ 6 x ⋅ 1 0 2 4 ⋅ 6 6 ⋅ 3 4 3 ≡ 6 ⋅ 4 ⋅ 6 ⋅ 3 c c c c c c c c c c powers of 6 always and with a 6 (see Note) ≡ 2 4 ⋅ 1 8 ≡ 4 ⋅ 8 ≡ 3 2 ≡ 2 m o d 1 0
Note:
Let x be a positive integer
{ 6 x ≡ 0 x ≡ 0 m o d 2 6 x ≡ 1 x ≡ 1 m o d 5
By the CRT
6 x ≡ 6 m o d 1 0