The function satisfies for all real numbers . If the equation has exactly four distinct real roots, find the sum of these roots.
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Substitute x = a − 2 we get
f ( a ) = f ( 4 − a )
This if x is a solution, 4-x is a solution.
Now, x represents all values of x possible. Let's substitute p and q for two SPECIFIC distinct values of the 4 possible roots of this function.
We have the solutions p , 4 − p , q , 4 − q
If we sum these we get
4 − p + p + 4 − q + q = 8