Unsquare me

We just have to use the identity $a^{2}-b^{2} = (a+b)(a-b)$ to split the numerator as follows:

$\frac{(33^{2}-27^{2})}{(33-27)}$ = $\frac{(33-27)(33+27)}{(33-27)}$ = $(33+27) = 60$

$$\frac{33^2 - 27^2}{33-27} = \frac{(33+27)(33-27)}{33-27} = 33+27 = 60$$

(33^2-27^2)/33-27 =(33+27)(33-27)/33-27 by using the identity:- a^2-b^2=(a+b)(a-b) =33+27 =60

$\frac{(33^{2} -27^{2})}{(33-27)}$

= $\frac{(33+27)(33-27)}{33-27}$

= ${(33+27)}$

= $60$

(33^2) - (27^2) = (33 - 27) (33 +27 )

remeber / lembre-se: x.x - y.y = (x +y).(x-y), then/ portanto: (x + y). (x -y)/ (x -y) = x+y = 33+27= 60

apply a^2 - b^2=(a+b)(a-b)

(33x33 - 27x27)/(33-27) = (33+27)(33-27)/(33-27) = (33+27) = 60 (Ans.)

33^2-27^2/33-27 =(33+27)(33-27)/(33-27) =33+27=60

We can factor the numerator as $(33+27)(33-27)$ . Dividing by $33-27$ yields $33+27= \fbox{60}$

$\frac{(33^2 - 27^2)}{(33 - 27)}$ ........................This is the question

= $\frac{(33 + 27)(33 - 27)}{(33 - 27)}$ ................factorized using the identity $a^2 - b^2 = (a + b)(a - b)$ ................therfore the remaining is only:

= $(33 + 27)$ = $60$ .................. The Answer

1089 - 729 = 360

33 - 27 = 6

360/6=60

(33^2-27^2)/33-27 a^2-b^2=(a+b)(a-b),

(33+27)(33-27)/33-27,

33+27=60

{33^2 - 27^2}{33-27} = \frac{(33+27)(33-27)}{33-27} = 33+27 = 60

(33^2-27^2)/33-27 = (3^2 11^2 - 3^2 9^2)/(3 11-3 9) = 3^2(11^2-9^2)/3(2) = 3(121-81)/2 = 60

(33-27)(33-+27)/(33-27)=(33+27)=(60)

as we know (a^2 - b^2) = (a + b) (a - b)

(1089-729)/(6)

(33^2-27^2)/(33-27) =(33-27)(33+27)/(33-27) =60

(33^2-27^2)/33-27 a^2-b^2=(a+b)(a-b)

(33+27)(33-27)/33-27

33+27=60

[(33-27)x(33+27) ]/(33-27) =33+27=60

(33^2-27^2)/(33-27)=(33+27).(33-27)/(33-27)=(33+27)=60

just press the calculator. (33^2 - 27^2)/(33-27) = 360/ 6 = 60

=((33^2)-(27^2))/(33-27) =(1089-729)/6 =360/6 =60

sq(a)-sq(b)=(a+b)(a-b); a+b=33+27=60.

33^2 - 27^2 Can Be Written As (33-27)(33+27) Now The (33-27) Terms Cancels With The Denominator Thus We Get Answer As 33+27=60

(33-27)(33+27)/(33-27)=60

1089-729/33-27

360/6=60

a^2 - b^2 =( a+b) (a-b)

so,

(33+27) (33-27)/(33-27)

= 60

We know that , a square - b square =(a-b)(a+b) Here a=33 and b=27 Therefore, 332-272=(33-27)(33+27) Therefore, (332-272)/(33-27) = [(33+27)(33-27)]/(33-27) = (33+27) Since (33-27) in numerator cancels with (33-27) in denominator = 60

the given no is in the format (a^2 - b^2) /(a - b) i.e (a+b)(a-b)/(a-b) = (a +b ) = (33+27) = 60

x= (square of a - square of b) divided by (a-b) identity

In that kind of equation presented in the problem, it is obvious that our numerator(or dividend either) is factor-able since 33^2-27^2 is a representation of a common special product which is a^2-b^2 and the denominator(or divisor) is a factor of 33^2-27^2. Therefore, the quotient of the said equation is 33+27 and by means of adding I derive the solution of 60.

a a-b b=(a-b)(a+b) therefore, (33+27)(33-27)/(33-27)=33+27=60

a²-b²=(a+b)*(a-b)

33²-27²=(33-27)*(33+27)

(33-27)*(33+27)/(33-27) = (33+27) = 60

33^2=1089 , 27^2=729 , 1089-729= 360 , And 33-27=6 , So 360 / 6 = 60.

(33+27) (33-27)/(33-27)=60

a a-b b=(a-b)(a+b)