Which of the expressions below is factorizable?
Q 1 ( p ) = [ p − ( 2 m + 1 ) n ] [ p − ( 2 m − 1 ) n ] . . . [ p − n ] [ p + n ] . . . [ p + ( 2 m − 1 ) n ] [ p + ( 2 m + 1 ) n ] − 1
Q 2 ( p ) = [ p − ( 2 m + 1 ) n ] 2 [ p − ( 2 m − 1 ) n ] 2 . . . [ p − n ] 2 [ p + n ] 2 . . . [ p + ( 2 m − 1 ) n ] 2 [ p + ( 2 m + 1 ) n ] 2 + 1
Note: 0 = m = n = p ∈ Z .
This is part of the series: " It's easy, believe me! "
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Problem Loading...
Note Loading...
Set Loading...
This is not actually a solution, but rather a generalization, that:
( x − a 1 ) ( x − a 2 ) . . . ( x − a n − 1 ) ( x − a n ) − 1 and ( x − a 1 ) 2 ( x − a 2 ) 2 . . . ( x − a n − 1 ) 2 ( x − a n ) 2 + 1 are both unfactorizable in Z [ x ] , n ∈ N ∗ and a 1 = a 2 = ⋯ = a n − 1 = a n ∈ Z .
Q 1 ( p ) and Q 2 ( p ) are just a small part in this qeneralization, making a problem more specific sometimes makes the problem harder, right?