Unusual Faster-Than-Speed-of-Light Situation

A physics student attaches a laser pen to an ultra-fast robotic arm, pointing it at the moon. Consider a spherical moon, in which the laser is visible as a dot. A single rapid flick of the arm moves the dot from point A A to point B B in a 120 degree arc through the lunar surface. Calculate the maximum interval of time Δ t max \Delta t_{\text{max}} , in milliseconds , in which the movement of the arm could take place so that the laser dot moves twice as fast as the speed of light c c in the lunar surface.

Details and assumptions

  1. Lunar radius is = 1737.1 km = 1737.1 \text{ km} .
  2. Speed of light is c = 3 × 1 0 5 km/s c = 3 \times 10^{5} \text{ km/s} .
  3. Take π = 3.14 \pi = 3.14 .
  4. The result is a single digit integer


The answer is 6.

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1 solution

Akshit Srivastava
Dec 31, 2015

Dist=2(pi) 1737.1 multiplied by 10^3 multiplied by (1/3) Speed=6 10^8 Time= dist./speed

Why is the speed 610^8 m/s ?

Lim Yu - 5 years, 5 months ago

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