Ulrich has a first generation iPod, which has 512 MB of memory space. If each of his songs takes up exactly 8 MB of space, how many songs can he can store on his iPod?
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512 fracture 8 est égal à 64
Divide 512 8=64
8=64
512 by=64
lame
M E M O R Y S P A C E F O R E A C H S O N G T O T A L M E M O R Y S P A C E 8 5 1 2 = 64
Ulrich can save the songs in his iPod = 512/8 = 64 songs
Total space is 512MB and size of each songs is 8MB Thus No. of tracks in the ipod are 512 / 8 = 64 That is answer.
Total space is 512MB
and size of each songs is 8MB
Thus No. of tracks in the ipod are 512 / 8 = 64 That is answer.
512/8=64 is the answer
Total Memory = 512 MB Song Space = 8 MB
hence, total number of songs = 512/8 =64
512 = 8 * y (where 'y' is number of songs and * means multiplication) 512/ 8 = y 64 = y therefore number of song is 64
512 MB (memory space) / 8 MB(song) = 64songs
as it is given that the ipod has 512 mb of space n each songs take 8mb of space to find no of songs we hive to divide 512 by8
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i divide 512 by 8= 64