Straight From P To Q. Well, Not Really

Geometry Level 4

Consider a quadrilateral A B C D ABCD with A B = 16 AB=16 , B C = 8 BC=8 , C D = 8 CD=8 and A B C = B C D = 9 0 \angle ABC = \angle BCD = 90^{\circ} . Let P P be a point on A B AB such that A P = 2 AP=2 and let Q Q be a point on C D CD such that D Q = 3 DQ=3 .

Find the length of the shortest path which:

  • Begins at P P , then
  • Meets the side D A DA at a point W W , then
  • Meets the side B C BC at a point X X , then
  • Meets the side D A DA again at a point Y Y , then
  • Meets the side A B AB at a point Z Z , and then
  • Ends (finally) at Q Q .


The answer is 41.

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1 solution

Maria Kozlowska
Jan 23, 2016

Relevant wiki: Reflection

Reflection is the answer.

4 0 2 + 9 2 = 41 \sqrt{40^2 + 9^2}=41

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