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Algebra Level 1

If f ( x ) = 1 x + 1 , f(x)=\frac{1}{x}+1, find k = 1 2018 f ( k ) = f ( 1 ) × f ( 2 ) × f ( 3 ) × × f ( 2017 ) × f ( 2018 ) . \prod_ {k=1} ^{2018} f(k) =f(1) \times f(2) \times f(3)\times \cdots\times f(2017)\times f(2018).


The answer is 2019.

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1 solution

Diego Perez
Apr 30, 2018

We have: f ( x ) = 1 x + 1 = 1 + x x f(x)=\frac{1}{x}+1 =\frac{1+x}{x} , so

f ( 1 ) × f ( 2 ) × f ( 3 ) × × f ( 2017 ) × f ( 2018 ) = 2 1 × 3 2 × 4 3 × × 2019 2018 = 2019 1 = 2019 f(1) \times f(2) \times f(3)\times \cdots\times f(2017)\times f(2018)=\frac{2}{1}\times \frac{3}{2}\times \frac{4}{3}\times \cdots \times \frac{2019}{2018} =\frac{2019}{1}=\boxed{2019}

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