W X and Y Z are parallel lines and S V and P R are transversals. The size of angle R Q Y is 6 1 ° and the size of angle Q U T is 4 2 °
What is the size of angle U T P in degrees?
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a = 6 1 ∘
b = 1 8 0 ∘ − a − 4 2 ∘ = 1 8 0 ∘ − 6 1 ∘ − 4 2 ∘ = 7 7 ∘
c = 1 8 0 ∘ − b = 1 8 0 ∘ − 7 7 ∘ = 1 0 3 ∘
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Angles RQY and PTX are alternate exterior angles, so are equal
⇒ ∠ P T X = 6 1 °
Angles QUT and UTX are alternate interior angles, so are equal ⇒ ∠ U T X = 4 2 °
So, ∠ U T P = ∠ U T X + ∠ P T X = 4 2 ° + 6 1 ° = 1 0 3 °