Valentine's Day Problem 1

How many different rearrangements of the letters in the word VALENTINE are there?


The answer is 90720.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Harsh Khatri
Feb 16, 2016

There are 9 letters out of which 2 are repeated twice. So, total number of words (including VALENTINE) :

9 ! 2 ! 2 ! = 90720 \displaystyle \Rightarrow \frac{9!}{2!\cdot 2!} = \boxed{90720}

That is not right. Not all two letters are words.

Thomas Anderson - 5 years, 3 months ago

Log in to reply

Didn't get you. Can you be more clear about what you're asserting?

Harsh Khatri - 5 years, 3 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...