Value of c=?

Calculus Level 2

For which value of the constant c c is the function f ( x ) f(x) continuous on ( , ) (-\infty,\infty\big) ?

f ( x ) = { c 2 x c x 1 c x x x > 1 f(x) =\begin{cases} c^2x -c & x \le 1 \\ cx-x & x>1 \end{cases}


The answer is 1.

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2 solutions

Hana Wehbi
May 29, 2018

f ( x ) = { c 2 x c x 1 c x x x > 1 f(x) =\begin{cases} c^2x -c & x \le 1 \\ cx-x & x>1 \end{cases}

The partial functions of f ( x ) f(x) are continuous for x < 1 x<1 and x > 1 x>1 .(since they are polynomials)

To get f ( x ) f(x) continuous on ( , ) (-\infty,\infty\big) :

we need lim x 1 f ( x ) = lim x 1 + f ( x ) = f ( 1 ) \lim_{x\to 1^-} f(x) = \lim_{x\to 1^+} f(x)=f(1) .

This happens only when c 2 c = c 1 c 2 2 c + 1 = 0 ( c 1 ) 2 = 0 c = 1 c^2-c=c-1\implies c^2-2c+1=0 \implies (c-1)^2=0 \implies c=\boxed{1}

X X
May 29, 2018

Placa x = 1 x=1 , c 2 c = c 1 c = 1 c^2-c=c-1\rightarrow c=1

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