Ladenburg found that a sample of ozonised Oxygen containing 86.16% of O3 by WEIGHT required 430 sec to diffuse under conditions where pure O2 required 369.5 sec . Determine the Vapour Density of O3
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Use Graham law of diffusion to find Equivalent molecular mass of mixture I.e 43.337g/mol.
Assume 100 g of mixture having 86.16 g as ozone and 13.84 g as oxygen.
Having molecular mass of oxygen as 32 g/mol, use it in the next formula.
Total moles in mixture is equal to sum of moles of components of mixture.
So, 86.16/m + 13.84/32 = 100/43.337
m=45.954.
Vapour density is half of molecular mass of sample so it will be 22.9772 .
It's best approximation according to the options is 23.3 .