Vector Addition?

Find the temperature of junction if rods are identical and are placed symmetrically.

110 110 ℃ 320 320 ℃ 90 90 ℃ 175 175 ℃ 85 85 ℃ 95 95 ℃ 80 80 ℃ None of these

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2 solutions

Abhishek Sinha
Dec 11, 2015

It follows from the solution of the time-invariant two-dimensional heat equation 2 u ( x , y ) = 0 \nabla^2 u(x,y)=0 that, temperature at any point in the steady-state is the average of the temperatures of the neighbouring points. Thus the temperature at the junction is T = 1 4 ( 100 + 100 + 50 + 70 ) C = 8 0 C T=\frac{1}{4}\big(100+100+50+70)^\circ C=80^\circ C

Pulkit Gupta
Dec 12, 2015

Assuming the value of junction as θ \theta and applying Kirchoff's Junction rule for heat currents, we get

100 - θ \theta + θ \theta = θ \theta - 70 + θ \theta - 50 { heat entering the junction from the two rods at higher temperatures is equal to the heat exiting the junction to the rods at lower temperatures)

On solving, we get θ \theta = 80

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