Vector components and length

Algebra Level 1

Consider vector P Q → \overrightarrow{PQ} defined by initial and terminal points P = ( 3 , 2 , 0 ) , Q = ( 5 , − 2 , 0 ) . P=(3, 2, 0), Q=(5, -2, 0). What is the unit vector in the direction of P Q → ? \overrightarrow{PQ}?

( 1 11 , − 5 7 , 0 ) \left(\frac { 1 }{ \sqrt { 11 } } , -\frac { 5 }{ \sqrt { 7 } } , 0\right) ( 1 7 , − 1 7 , 0 ) \left(\frac { 1 }{ \sqrt { 7 } } , -\frac { 1 }{ \sqrt { 7 } } , 0\right) ( 1 5 , − 2 5 , 0 ) \left(\frac { 1 }{ \sqrt { 5 } }, -\frac { 2 }{ \sqrt { 5 } },0\right) ( 1 3 , − 6 5 , 0 ) \left(\frac { 1 }{ \sqrt { 3 } } , -\frac { 6 }{ \sqrt { 5 } } , 0\right)

View wiki
Lawahar Qasid by Lawahar Qasid

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Gaurav Waghmare
May 9, 2014

Magnitude of unit vector = 1. Magnitude of a three dimensional vector = √x²+y²+z²

2 Helpful 0 Interesting 0 Brilliant 0 Confused

I tried a simple approach. forget the Z component. subtracting X {2} - X {1} and doing the same with the Y components, we get it to be 2,-4,0. dividing by \frac{2}{\sqrt{5}}, we get the answer. im not sure whether its flawless r not but i sure did get the answer.

Krishna Deb - 7 years, 1 month ago

Sorry but can someone explain me in detail about dis one.....

priyanka patil - 7 years ago

Pleese can any one explane me in detail

vijay thakur - 6 years, 11 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...