Vector Dot Product (3D)

Algebra Level 1

For

A = ( 1 , 4 , 7 ) , B = ( 2 , 6 , 4 ) , C = ( 1 , 9 , 8 ) , A=(1, 4, 7), B=(2, 6, 4), C=(1, 9, 8) ,

what is the dot product of A A and ( B C ) ? (B-C)?


The answer is -39.

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1 solution

A = i ^ + 4 j ^ + 7 k ^ \vec A = \hat i + 4 \hat j + 7 \hat k

B = 2 i ^ + 6 j ^ + 4 k ^ \vec B = 2 \hat i + 6 \hat j + 4 \hat k

C = i ^ + 9 j ^ + 8 k ^ \vec C = \hat i + 9 \hat j + 8 \hat k

B C = i ^ 3 j ^ 4 k ^ \vec B - \vec C = \hat i - 3 \hat j - 4 \hat k

A ( B C ) = 1 12 28 = 39 \therefore \vec A \cdot (\vec B - \vec C) = 1 - 12 - 28 = - 39

(Note that all terms with ij, ik, and jk in the dot product are zero)

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