Vector space problem
The value of "k" for which the two vectors (k,6) and (2,k) form a basis of can not be where a and b are positive integers.Find a+b.
The answer is 5.
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1 solution
ks+2t=0 and 6s+kt=0 since (k,6) and (2,k) form a basis, they are linearly independent therefore s=t=0 therefore k/6 cannot be equal to 2/k which implies k^2 cannot be equal to 12 k=/=±2√3 a+b=5