V e e e e e e e e e e e e R M S \color{#69047E}{Veeeeeeeeeeee RMS}

Classical Mechanics Level 3

Considering H 2 \ce H_2 ; H e \ce{He} ; N X 2 { \ce{N2} } ; O X 2 {\ce{O2}} show ideal behavior at room temperature the Translational Kinetic energy per molecule for the following gases will be in order

O 2 > N 2 > H e > H 2 { O }_{ 2 }>{ N }_{ 2 }>He>{ H }_{ 2 } O 2 < N 2 < H e < H 2 { O }_{ 2 }<{ N }_{ 2 }<He<{ H }_{ 2 } O 2 = N 2 = H e = H 2 { O }_{ 2 }={ N }_{ 2 }=He={ H }_{ 2 } NONE OF THESE

Jaswinder Singh by Jaswinder Singh , 23, India

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1 solution

Jaswinder Singh
Feb 20, 2016

K . E = 1 2 m ( V R M S ) 2 = 1 2 m ( 3 k T m ) 2 = 3 2 k T K.E=\frac { 1 }{ 2 } m{ ({ V }_{ RMS }) }^{ 2 }=\frac { 1 }{ 2 } m{ (\sqrt { \frac { 3kT }{ m } } ) }^{ 2 }=\frac { 3 }{ 2 } kT as seen above the kinetic energy per molecule is independent of mass of molecule

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