Velocity Problem
Level
pending
A ball is thrown upward with an initial velocity of +9.8 m/s. How high does it reach before it starts descending?
Note: acceleration due to gravity= -9.8 m/s²
76.44 meters
4.9 meters
Not enough information
9 meters
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1 solution
You solve it as if you are looking for the equivalent of x
Use the formula:
final velocity² = initial velocity² + 2(acceleration due to gravity)(distance)
Final velocity= 0
initial velocity= +9.8 m/s
acceleration due to gravity= 9.8 m/s
distance or d= ?
Solution
0² = (9.8)² + 2(-9.8)(d)
0=96.04 + -19.6d
19.6d=96.04
(Cancel the 19.6, leaving d= 96.04 ÷ 19.6)
d = 4 . 9 m e t e r s