Versatile Sum and Difference of Squares

How many integers cannot be expressed in the following form, where x x , y y , and z z are integers?

x 2 y 2 + z 2 \large x^2 - y^2 + z^2


The answer is 0.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Hongqi Wang
Oct 31, 2020

( n + 1 ) 2 n 2 = 2 n + 1 (n+1)^2 - n^2 = 2n + 1 can cover all odd.

  • let z = 0 , x = n + 1 , y = n z= 0, x = n+1, y = n , then ( x 2 y 2 + z 2 ) (x^2 - y^2 + z^2) can express all odd

  • let z = 1 , x = n + 1 , y = n z = 1, x = n+ 1, y = n , then ( x 2 y 2 + z 2 ) (x^2 -y ^2 + z^2) can express all even

Thank youo!

Alexander Shannon - 7 months, 1 week ago
Naufal Fadil
Oct 31, 2020

Just a note: x 2 y 2 = ( x + y ) ( x y ) x^2 - y^2 = (x + y)(x - y) can take on any even integer divisible by 4 4 , not just zero. Just choose x = n + 1 x = n + 1 and y = n 1 y = n - 1 to get 4 n 4n . x 2 y 2 = ( n + 1 ) 2 ( n 1 ) 2 = ( n 2 + 2 n + 1 ) ( n 2 2 n + 1 ) = 4 n \begin{aligned} x^2 - y^2 &= (n+1)^2 - (n-1)^2 \\ &= (n^2+2n+1) - (n^2-2n+1) \\ &= 4n \end{aligned} But it is impossible to get even integers like ± 2 , ± 6 , ± 10 , . . . \pm 2, \pm 6, \pm 10, ... from x 2 y 2 x^2 - y^2 .

Matthew Feig - 7 months, 1 week ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...