Find the minimum velocity the bob has of mass 0.5 kg when the string is horizontal (in vertical circle). Length of string = R
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When the ball is at the highest point,
T+mg=[m(u)^2]/R
minimum velocity at the top is achieved when T=0. So u=(gR)^(1/2).
According to conservation of energy,
mg2R+[m(u)^2]/2=mgR+[m(v)^2]/2
So the minimum velocity is (3gR)^(1/2).