Vertical Problem

Find the minimum velocity the bob has of mass 0.5 kg when the string is horizontal (in vertical circle). Length of string = R

root of (2gR) 3gR root of (3gR) 2gR

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2 solutions

Yuen Ho Lam
Sep 18, 2015

When the ball is at the highest point,

T+mg=[m(u)^2]/R

minimum velocity at the top is achieved when T=0. So u=(gR)^(1/2).

According to conservation of energy,

mg2R+[m(u)^2]/2=mgR+[m(v)^2]/2

So the minimum velocity is (3gR)^(1/2).

Department 8
Sep 16, 2015

To get the minimum velocity at the horizontal you should have minimum velocity at the base, which we know is 5 g r \sqrt{5gr} applying conservation of energy you will get answer as 3 g r \sqrt{3gr}

yep it is,any intresting physics question

Kaustubh Miglani - 5 years, 8 months ago

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