A geometry problem by Ahmed Moh AbuBakr

Geometry Level 2

A B C ABC is an isosceles triangle such that A B = A C AB = AC and B A C M C B = a b \frac {\angle BAC}{\angle MCB} = \frac a b for coprime positive integers a , b a,b . What is the value of a + b a+b ?


The answer is 3.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Let P P be the midpoint of B C . BC. Then Δ A P B \Delta APB , Δ A P C \Delta APC and Δ C M B \Delta CMB are all similar, and thus y = 2 x y x = 2. y = 2x \Longrightarrow \dfrac{y}{x} = 2.

With a , b a,b coprime, we then have that a + b = 2 + 1 = 3 . a + b = 2 + 1 = \boxed{3}.

WE can write (90-y)+x=180-(90+x). This gives y=2x and y/x=2/1.Thus a+b=3.

Siddharth Singh - 6 years, 1 month ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...