Very Large Primes Indeed !
Level
pending
Find the number of primes in the sequence -
2013!+2, 2013!+3, 2013!+4, 2013!+5, ...................., 2013!+2013.
The answer is 0.
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1 solution
In this sequence - 2013!+2=(2xa)+2[for some integer a] =2(a+1). Therefore it is not a prime because it has 2 distinct factors 2 and (a+1). Similarly 2013!+3=(3xb)+3[For some integer b] =3(b+1). Therefore It is also not a prime. By going with this process we find that - 2013!+2013= (2013xz)+2013[For some integer z] =2013(z+1). Therefore it is also not a prime. So we find that there are no primes in this sequence. Hence the answer is 0(zero).