very odd!

Level pending

(1+3+5+7+.....+2p-1)+(1+3+5+7...+2q-1)=(1+3+5+....+2r-1)

What is the smallest possible value of $p \times q \times r$

2 solutions

Washeef Mohammad
Dec 25, 2013

$1+3+5+7+.....+(2n-1)= n^{2}$

$p^{2}+q^{2}=r^{2}$ $\Rightarrow 3^{2}+4^{2}=5^{2}$ being the smallest Pythagorean triples

$3\times 4 \times 5= 60$

Raghu Ram
Dec 25, 2013

P^2+q^2=r^2.it implies 3,4,5