Very simple roots

Algebra Level 3

A polynomial

p ( x ) = x n + a n 1 x n 1 + + a 2 x 2 + a 1 x + a 0 p(x) = x^n + a_{n-1}x^{n-1} + \cdots + a_2x^2 + a_1x + a_0

of degree n n may be called simple if it satisfies the following conditions:

  • All coefficients are integers
  • Its n n roots r 0 , 1 , , n 1 r_{0,1,\ldots,n-1} are all real and distinct
  • For every root r i r_i there is exactly one coefficient a j a_j such that r i = a j r_i = a_j .

Does there exist a simple polynomial of degree n 1 n \geq 1 ?

Yes No

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2 solutions

Henry U
Nov 18, 2018

An example is p ( x ) = x 2 + 1 x 2 p(x) = x^2 + {\color{#D61F06}1}x {\color{#3D99F6}- 2} which has roots r = 1 , 2 r = {\color{#D61F06}1},{\color{#3D99F6}-2} .

Abhishek Sinha
Nov 21, 2018

Take p ( x ) = x 2 1. p(x)=x^2-1.

Techhnically, its coefficients are 0 and –1, but 0 isn't one of its roots, which are ±1.

I let it count though because you're not writing 0x, so the 0 isn't really present.

Henry U - 2 years, 6 months ago

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