Vicious Circles And Savage Shapes

Geometry Level 1

The following figure consists of a large semicircle of diameter 20 cm 20\text{ cm} , a smaller full circle of diameter 10 cm 10\text{ cm} , a semicircle of diameter 5 cm 5\text{ cm} , a quadrant of radius 5 cm 5 \text{ cm} , and a right-angled triangle of sides 20 cm 20\text{ cm} and 10 cm 10\text{ cm} . Find the shaded area in cm 2 \text{cm}^2 .

Give your answer to 1 decimal place.

125.4 145.4 185.8 190.6

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1 solution

Wee Xian Bin
Jul 9, 2016

Relevant wiki: Length and Area - Composite Figures

Dissect the figure into the following:

Then notice that:

Therefore:

A + C + D + E = ( 1 2 ) ( π ) ( 10 ) 2 + ( 1 2 ) ( π ) ( 10 2 ) 2 ( 1 2 ) ( 20 ) ( 10 ) = 96.35 A+C+D+E=(\frac{1}{2})(\pi)(10)^2+(\frac{1}{2})(\pi)(\frac{10}{2})^2-(\frac{1}{2})(20)(10)=96.35

B = ( 1 4 ) ( 1 2 ) ( 20 ) ( 10 ) = 25 B=(\frac{1}{4})(\frac{1}{2})(20)(10)=25

H = ( 10 2 ) 2 ( 1 4 ) ( π ) ( 10 2 ) 2 = 5.37 H=(\frac{10}{2})^2-(\frac{1}{4})(\pi)(\frac{10}{2})^2=5.37

F + G = ( 1 2 ) ( π ) ( 10 2 ) 2 ( 1 2 ) ( π ) ( 10 4 ) 2 H = 24.08 F+G=(\frac{1}{2})(\pi)(\frac{10}{2})^2-(\frac{1}{2})(\pi)(\frac{10}{4})^2-H=24.08

And as such A + B + C + D + E + F + G = 145.4 A+B+C+D+E+F+G=145.4

Great use of the De Morgans law and the fact A B + A B = A + B A \cup B + A \cap B = A + B .

Jerry McKenzie - 4 years ago

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