Volume and pressure equivalence

Chemistry Level 2

A balloon is inflated with helium gas at room temperature of 2 5 C 25^\circ C and at 1 b a r 1bar pressure when its initial volume is 3.0 L 3.0\text{ L} and allowed to rise in air. As it rises in air external pressure decreases and volume of gas increases till finally it bursts when external pressure is 0.3 b a r 0.3bar .What is the limit to which volume of the balloon can be inflated?

Given :
P r e s s u r e ( 1 ) = 1 b a r Pressure(1)=1bar , V o l u m e ( 1 ) = 3.0 L Volume(1)=3.0L

P r e s s u r e ( 2 ) = 0.3 b a r Pressure(2)=0.3bar , V o l u m e ( 2 ) = ? Volume(2)=?


The answer is 10.

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1 solution

As given P 1 = 1 b a r , P 2 = 0.3 b a r , V 1 = 3.0 L , V 2 = ? P_{1}=1bar,P_{2}=0.3bar,V_{1}=3.0L,V2=?

as gas equation P V = n R T PV= nRT ,here temperature,number of mole are constant and pressure ,volume has change. so we can assume that,

P 1 V 1 = n R T P_{1}V_{1}=nRT and P 2 V 2 = n R T P_{2}V_{2}=nRT one side is equal so other must be,

so, P 1 V 1 = P 2 V 2 P_{1}V_{1}=P_{2}V_{2 }

For Volume V 2 , V_{2}, V 2 = ( P 1. V 1 ) / P 2 V_{2}=(P1.V1)/P2 V 2 = ( 1 3 ) / 0.3 = 10 L V_{2}=(1*3)/0.3= 10L

Volume of the balloon can be inflated to 10 L 10L .

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