Surface areas and Volumes are haunting!

According to the question, $\frac { 1 }{ 3 } TSA=CSA$

$\frac { 2\pi { r }^{ 2 }+2\pi rh\quad }{ 3 } =\quad 2\pi rh\quad\\2\pi { r }^{ 2 }=\quad 6\pi rh-2\pi rh\\2\pi { r }^{ 2 }=\quad 4\pi rh\\2\pi { r }=\quad 4\pi h\\2{ r }=\quad 4h\quad \\{ r }=\quad 2h\\2\pi rh=\frac { 462 }{ 3 } =154\quad\\2\pi (2h)h=154\\{ h }^{ 2 }=\frac { 154\times 7 }{ 22\times 2\times 2 } \quad\\{ h }=\frac { 7 }{ 2 } \quad\\{ r }=7\quad\\\pi { r }^{ 2 }h=\frac { 22 }{ 7 } .7.7.\frac { 7 }{ 2 } \\\pi { r }^{ 2 }h=\quad 539$