Volumes?

Calculus Level 3

What is the volume bounded by the regions boubded by the graphs of the equation z = x 2 , z = x 3 , y = z 2 , y = 0 z = x^2, z = x^3, y = z^2, y = 0 ?

Let the answer to this question be A A . Then give your answer as 1000 A \left \lfloor 1000A \right \rfloor .


Source: Peter Dunsby.


The answer is 14.

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1 solution

Ashish Menon
Jun 3, 2016

V = 0 1 x 3 x 2 0 t 2 d y d t d x = 0 1 x 3 x 2 [ y ] 0 t 2 d t d x = 0 1 x 3 x 2 t 2 d t d x = 0 1 [ 1 3 t 3 ] x 3 x 2 d x = 1 3 0 1 ( x 6 x 9 ) d x = 1 3 [ 1 7 x 7 1 10 x 10 ] 0 1 = 1 3 × ( 10 7 ) 70 = 1 70 A = 0.01428 1000 A = 14 \begin{aligned} V & = \int_{0}^{1} \int_{x^3}^{x^2} \int_{0}^{t^2} \ dy \ dt \ dx\\ \\ & = \int_{0}^{1} \int_{x^3}^{x^2} \left[ y \right]_{0}^{t^2} \ dt \ dx\\ \\ & = \int_{0}^{1} \int_{x^3}^{x^2} t^2 \ dt \ dx\\ \\ & = \int_{0}^{1} \left[\dfrac{1}{3} t^3\right]_{x^3}^{x^2} \ dx\\ \\ & = \dfrac{1}{3} \int_{0}^{1} \left(x^6 - x^9\right) \ dx\\ \\ & = \dfrac{1}{3} \left[\dfrac{1}{7} x^7 - \dfrac{1}{10} x^{10}\right]_{0}^{1}\\ \\ & = \dfrac{1}{3} × \dfrac{\left(10 - 7\right)}{70}\\ \\ & = \dfrac{1}{70}\\ \implies A & = 0.01428\\ \implies \left \lfloor 1000A \right \rfloor & = \color{#69047E}{\boxed{14}} \end{aligned}

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