w

Algebra Level pending

w^5+w^4+1


The answer is 0.

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2 solutions

Sujit Kumar
May 7, 2015

ok from next time

Archit Boobna
Mar 21, 2015

It should be mentioned that w is the imaginary cube root of unity.

w 3 = 1 a n d w 1 S o , w 3 1 = 0 ( w 1 ) ( w 2 + w + 1 ) = 0 w 1 0 , s o w 2 + w + 1 = 0 S o w 3 ( w 2 + w + 1 ) = 0 S o w 5 + w 4 + w 3 = 0 S o w 5 + w 4 + 1 = 0 { w }^{ 3 }=1\quad and\quad w\neq 1\\ So,\quad \\ { w }^{ 3 }-1=0\\ \left( w-1 \right) \left( { w }^{ 2 }+w+1 \right) =0\\ w-1\neq 0,\quad so\quad { w }^{ 2 }+w+1=0\\ So\quad { w }^{ 3 }\left( { w }^{ 2 }+w+1 \right) =0\\ So\quad { w }^{ 5 }+{ w }^{ 4 }+{ w }^{ 3 }=0\\ So\quad { w }^{ 5 }+{ w }^{ 4 }+1=0

Sujit Kumar This guy is right, you should let us know what w w stands for, I never knew until I read this solution.

Micah Wood - 6 years, 2 months ago

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