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It should be mentioned that w is the imaginary cube root of unity.
w 3 = 1 a n d w = 1 S o , w 3 − 1 = 0 ( w − 1 ) ( w 2 + w + 1 ) = 0 w − 1 = 0 , s o w 2 + w + 1 = 0 S o w 3 ( w 2 + w + 1 ) = 0 S o w 5 + w 4 + w 3 = 0 S o w 5 + w 4 + 1 = 0
Sujit Kumar This guy is right, you should let us know what w stands for, I never knew until I read this solution.
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