Three boys have 4 coats, 5 waist coats and 6 caps. In how many ways can the boys wear them?
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Selection of clothes for three boys = 4C3 * 5C3 * 6C3=2400.
3 different coats can be used by 3 boys in 3! ways.
Same will be applied for waist coat and caps too.
So, 3! * 3! * 3! = 216, but one particular combination will be repeated for each boy.
total different combination for above selection = 216/3 = 72
hence total no of ways = 2400*72 = 172800