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Calculus Level pending

Let f ( x ) = x x f(x)=x^{x} and x is not equal to zero. Find the derivative of this function and find the value of the derivative at x = e x=e

23 32.1 30.3 29.8

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1 solution

Caleb Townsend
Mar 14, 2015

f ( x ) = x x = e x ln ( x ) d d x f ( x ) = ( e x ln ( x ) ) ( d d x x ln ( x ) ) = ( x x ) ( ln ( x ) + 1 ) f(x) =x^x = e^{x\ln(x)} \\ \frac{d}{dx}f(x) = (e^{x\ln(x)})(\frac{d}{dx}x\ln(x)) \\ = (x^x)(\ln(x) + 1)

f ( e ) = e e × 2 30.3 f'(e) = e^e\times 2 \\ \approx \boxed{30.3}

Try doing the same for s i n x ( x ) sin^x(x)

Anirudh Chandramouli - 6 years, 3 months ago

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f ( x ) = sin x ( x ) = e x ln ( sin ( x ) ) d d x f ( x ) = ( e x ln ( sin ( x ) ) ) d d x ( x ln ( sin ( x ) ) ) = sin x ( x ) ( ln ( sin ( x ) ) + x cot ( x ) ) f(x) = \sin^x (x) = e^{x\ln(\sin(x))} \\ \frac{d}{dx}f(x) = (e^{x\ln(\sin(x))})\frac{d}{dx}(x\ln(\sin(x))) \\ = \sin^x(x)(\ln(\sin(x)) + x\cot(x))

Caleb Townsend - 6 years, 3 months ago

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