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Geometry Level 3

If a = 1 , b = 2 , c = 3 , d = 4 a=1,b=2,c=3,d=4 , find x x .

Note: Figure is not to scale.

8 3 \frac{ 8}{3} 2 2 9 4 \frac{ 9}{4} 5 2 \frac{5}{2} 7 3 \frac{7}{3}

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2 solutions

As A B C D ABCD is cyclic, B A D B C E \angle BAD \cong \angle BCE and A D C C B E \angle ADC \cong \angle CBE , so E A D E B C \bigtriangleup EAD \sim \bigtriangleup EBC , so we have: E C 2 = x + 1 4 E C = x + 1 2 \frac{\overline{EC}}{2}=\frac{x+1}{4}\Rightarrow \overline{EC}=\frac{x+1}{2} x 2 = x + 1 2 + 3 4 4 x = x + 7 x 2 , 33 \frac{x}{2}=\frac{\frac{x+1}{2}+3}{4} \Rightarrow 4x=x+7 \Rightarrow x\approx 2,33

Ahmad Saad
Feb 15, 2016

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