Walking faster

Algebra Level 2

A man walks a distance of 48 km in a given time. If he had walked 2 km/hr faster, he would have completed the journey 4 hrs earlier. His normal rate of walking is:

5 km/hr
  • 6 km/hr or 4 km/hr
4 km/hr
  • 4 km/hr or 6 km/hr
6 km/hr

Sakanksha Deo by Sakanksha Deo , 23, India

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2 solutions

Azadali Jivani
Aug 14, 2015

distance = speed * time
d = 48 km, speed = xkm/hr, time = t hrs.
48 = x *t...............eq... 1
48 = (x=2)(t-4) eq...2
Now tx = (x+2)(t-4)
therefore t = 2x + 4
put value of t in eq..1
48 = (2x + 4)x
So x = 4 or -6
t = 48/4 =12
therefore speed = 48/12 = 4 (Ans.)

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Sai Karthik K A
Jul 17, 2015

let the speed of the man=k let the time taken be=t

STEP1:kt=48........(1)& (k+2)(t-4)=48.......(2)

STEP 2:from (1) and (2),

kt=(k+2)(t-4)

kt=kt+2t-4k-8

t-2k=4........(3)

STEP 3: put t=48/k in (3)

48/k - 2k=4( from 1&3)

solving we get,

k=4

therefore,speed of man=4 km/hr

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