In a shopping centre, an escalator is moving at steady speed between level one and two. There are n steps on the escalator. Aaron and Baron are walking up the escalator. Aaron's speed is twice Baron's speed. Given that Aaron walks up 2 7 steps from level one to level two and Baron takes 1 8 steps to do so, find n .
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54 steps? What a large elevator
Nice one Victor! :P
Let the escalator speed be e , t 1 the time for Aaron to go up, and t 2 the time for Baron to go up. Then we have the equation: 2 7 + e ∗ t 1 = 1 8 + e ∗ t 2 . So 9 = e ∗ t 2 ( 1 − t 2 t 1 ) . We also know that Aaron's speed is twice of Baron's speed, so t 1 2 7 = 2 ∗ t 2 1 8 , therefore t 2 t 1 = 4 3 . And we get e ∗ t 2 = 3 6 , the total number of steps is then 1 8 + 3 6 = 5 4 .
It might sound obvious but one has to first prove that the escalator is moving up and not down (because it is not mentioned in the question). And yeah, the proof cannot be that "Aaron and Baron are moving up the escalator, so the escalator must be moving up". This is math. Here, Tom buys 50 watermelons and 20 pencils just for the sake of a problem :P.
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If they were going in opposition of escalator than Baron would take more time resulting more steps he has to climb.... But in problem Aaron is climbing more step and his speed is also more... Thus we can say that they are moving with directions of escalator
Let Va, Vb, V be the velocity of a, b, and elevator. But Va = 2Vb.
Ta, time to move 27 steps by a, Tb for 18 by b.
Time = distance X velocity. Ta = 27/(2Vb) , Tb = 18/Vb
n = Time * actual velocity. n = Ta ( 2Vb + V ) also n = Tb ( Vb + V ) gives
{27/(2Vb)}
(2V + V ) = {18/Vb}
{Vb = V ) gives 2Vb = V = Va
Thus velocity of b and elevator is same thus elevator also moves 27 steps with b.
THUS TOTAL STEPS = 27 + 27 = 54.
simple logic guys...no hardcore mathematics!! i just started assuming numbers for n...strarted assuming with 36...45..and went on to 54...and satisfied...! see...if there are 54 steps...and 27 he aaron walked..it means 27 steps are gone by the speed of the escalator...it means..aaron's speed is 1 step walked as 1 step goes...now...baron's speed is half of it...soo..baron walks half step as 1 step goes ....which eventually ends up on 18 plus 36+ 54..! i know this method's gonna get a lot of BOO's...but it's my assumption method like everytime...:D!
let :v be Aaron's speed... t be time taken by Aaron to reach level 2... t' be time taken by baron to reach level 2... r be the number of steps moved by the escalator per unit of time... Aaron moved 27 steps during t instead of n, due to the escalator. hence, the ecalator moved (n-27) during t. so, r=((n-27)/t). Baron moved 18 steps during t' instead of n, due to the escalator. hence, the ecalator moved (n-18) during t'. so, r=((n-18)/t'). now, we will search for a relation between t and t'. we know: time=(steps/rate). so, t=27/v and t'=18/(v/2). using these two equations, we get t'=(4/3)t. substituting this in r=((n-18)/t'), and setting r=r, we will find n.
the solutions is Aarons walks up 27 and Baron takes 18 steps to do that this the solution is 27+27 coz Aarons speed is twice Barons Speed Regards ZAIN KHAN
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Person a's rate of escalator = Person b's rate of escalator
(n-27)/27 = (n-18)/36
n = 54 steps