If n ! = 1 2 0 , then what is the value of n ?
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1 ! = 1 2 ! = 2 3 ! = 6 4 ! = 2 4 5 ! = 1 2 0
Therefore, n = 5
We start with 1 multiply 2, we get 2, multiply 3 we get 6, multiply 4 we get 24 multiply 5 we get 120. So, 1 2 0 = 5 ! ⟹ n = 5 .
Knowng that each of the factorial values > 1 is unique, we can directly conclude: n ! = 1 2 0 = 5 ! < = > n = 5
n! = n x (n-1) x (n-2) x ... x 1 n x (n-1) x (n-2) x ... x 1 = 120 If we input n = 5, then 5 x 4 x 3 x 2 x 1 = 120 n = 5
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1 2 0 = 1 2 ⋅ 1 0 = 3 ⋅ 4 ⋅ 5 ⋅ 2 = 1 ⋅ 2 ⋅ 3 ⋅ 4 ⋅ 5 = 5 ! ⇒ n = 5