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Find The Value Of: cos 2 A + cos 2 ( A + 120 ) + cos 2 ( A 2 ) \cos ^{ 2 }{ A } +\cos ^{ 2 }{ (A+120) } +\cos ^{ 2 }{ (A-2) }


The answer is 1.5.

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1 solution

Soumo Mukherjee
Oct 15, 2014

Let S = cos 2 A + cos 2 ( A + 120 ) + cos 2 ( A 2 ) S=\cos ^{ 2 }{ A } +\cos ^{ 2 }{ (A+120) } +\cos ^{ 2 }{ (A-2) } ].

Then 2 S = 2 cos 2 A + 2 cos 2 ( A + 120 ) + 2 cos 2 ( A 2 ) 2 S = 2 cos 2 A + cos ( 2 A + 240 ) + 1 + cos ( 2 A 240 ) + 1 2 S = 2 cos 2 a + 1 cos 2 A + 2 2 S = 3 s = 3 / 2 2S=2\cos ^{ 2 }{ A } +2\cos ^{ 2 }{ (A+120) } +2\cos ^{ 2 }{ (A-2) } \\ \Rightarrow 2S=2\cos ^{ 2 }{ A } +\cos { (2A+240) } +1+\cos { (2A } -240)+1\\ \Rightarrow 2S=2\cos { 2a } +1-\cos { 2A } +2\\ \Rightarrow 2S=3\\ \Rightarrow s=3/2

Such transformations are important in many identities involving angles of a triangle.

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