Warm up problem 1

Calculus Level 3

If you are just waking up or just got on brilliant, here is a great problem to warm up your mind with. I am beginning a new set of problems that will be titled "warm up problems". In this set, I will be posting about 1-2 mainly easy to medium level problems to warm up with. Hope you enjoy!

If the minimum value of x 4 2 + 2 x 3 3 4 x 2 8 x + 2000 \frac{x^4}{2}+\frac{2x^3}{3}-4x^2-8x+2000 can be expressed as a/b for positive co prime integers a,b. Find a+b.


The answer is 5947.

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1 solution

Trevor Arashiro
Sep 16, 2014

We take the derivative and are left with

2 x 3 + 2 x 2 8 x 8 = 0 2x^3+2x^2-8x-8=0 .

Next, we factor it to

( x + 1 ) ( x + 2 ) ( 2 x 4 ) = 0 (x+1)(x+2)(2x-4)=0

x = 1 , 2 , 2 \therefore x={-1,-2,2}

Thus plugging in the possible values of x in the above equation to the original one, we find y=5944/3 to be the minimum value @ x=2. Thus our answer is 5947

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