If the value of
3 1 + 1 5 1 + 3 5 1 + . . . 4 8 3 1
Can be expressed as b a where a,b are positive co prime integers, find a+b.
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nice problem
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Thank you. It's great to have feed back so I know what and what not to post
I have finalized my solution so it is easier to understand. Please feel free to ask if you have any questions.
And who else thought that Heaviside was spelled heavy side... I honestly never knew how to spell it until I looked it up for my solution.
Could have called it Telescoping technique!! Rather than "Heavy side"! Lol! :P
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Finalized my solution. To understand this solution, it is helpful if you read this inorder to understand the Heaviside function. However, if you have trouble understanding this article or my solution, feel free to ask any question you may have. I'd be more than happy to answer it as telescoping functions are great but can get quite tricky.
By Heaviside function. a ( a + 2 ) 1 = 2 1 ( a 1 − a + 2 1 )
3 1 + 1 5 1 + 3 5 1 + . . . 4 8 3 1
1 × 3 1 + 3 × 5 1 + 5 × 7 1 + . . . 2 1 × 2 3 1
2 1 ( ( 1 − 3 1 ) + ( 3 1 − 5 1 ) + ( 5 1 − 7 1 ) . . . + ( 2 1 1 − 2 3 1 ) )
2 1 ( 1 − 2 3 1 )
2 3 1 1
1 1 + 2 3 = 3 4