Warm-up: Symmetry for the win! <3

You are on the coordinate grid at the point ( 1 , 1 ) (1, 1 ) and you do a 2 2 -dimensional completely random walk. Remember that each step size is ‘infinitesimal‘ and you can go in any direction, not just the 4 4 cardinal directions. Eventually you will cross the x-axis. What is the probability (to the 5 5 th decimal) that you cross the negative x-axis versus the positive x-axis first? Note: You may also consider a walk with fixed step size and regard the probability as step size approaches 0 0 ; If you prefer this way of thinking about the problem!

Note/Hint : Solvable by symmetry only; no calculator needed!

Note : Here is part 2 2 of the problem!


The answer is 0.25.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Simon Kaib
Jul 20, 2019

You have probability 1 2 \frac{1}{2} for crossing the y-axis before crossing the positive x-axis (since they have the same distance from the starting point). Once you are on the y-axis you have probability 1 2 \frac{1}{2} for crossing the negative x-axis before the positive x-axis (again, because they are symmetrical to the y-axis)! Thus you have a probability of 1 2 1 2 = 0.25 \frac{1}{2}\cdot\frac{1}{2}=0.25 for crossing the negative x-axis before the positive x-axis!

Draw the the 2 lines y=1 and the connection from (0,0) to (1,1). The angles created are 45 and 135 degrees respectively. The probability of first crossing x on "negative side" is 45/180=1/4

Eric Scholz - 1 year, 10 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...